0.5z^2+7(2)=z-5(z)

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Solution for 0.5z^2+7(2)=z-5(z) equation:


Simplifying
0.5z2 + 7(2) = z + -5(z)

Multiply 7 * 2
0.5z2 + 14 = z + -5(z)

Reorder the terms:
14 + 0.5z2 = z + -5(z)

Combine like terms: z + -5z = -4z
14 + 0.5z2 = -4z

Solving
14 + 0.5z2 = -4z

Solving for variable 'z'.

Reorder the terms:
14 + 4z + 0.5z2 = -4z + 4z

Combine like terms: -4z + 4z = 0
14 + 4z + 0.5z2 = 0

Begin completing the square.  Divide all terms by
0.5 the coefficient of the squared term: 

Divide each side by '0.5'.
28 + 8z + z2 = 0

Move the constant term to the right:

Add '-28' to each side of the equation.
28 + 8z + -28 + z2 = 0 + -28

Reorder the terms:
28 + -28 + 8z + z2 = 0 + -28

Combine like terms: 28 + -28 = 0
0 + 8z + z2 = 0 + -28
8z + z2 = 0 + -28

Combine like terms: 0 + -28 = -28
8z + z2 = -28

The z term is 8z.  Take half its coefficient (4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
8z + 16 + z2 = -28 + 16

Reorder the terms:
16 + 8z + z2 = -28 + 16

Combine like terms: -28 + 16 = -12
16 + 8z + z2 = -12

Factor a perfect square on the left side:
(z + 4)(z + 4) = -12

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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